Hydroboration-oxidation is yet another alcohol yielding alkene reaction. However this reaction results in an alcohol adding to the less substituted carbon for an anti-Markovnikov product.
The video below helps you understand the reactivity of Boron as well as the hydroboration and oxidation steps of the reaction mechanism.
Watch this video on YouTube or read the transcript (coming soon)
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I love your videos however, I would have loved to see the first reaction done as well. Do you have another video explaining this first reaction you have drawn?
What is the final product than that we normally need to show? Still a bit confused…
OH on the anti-markovnikov position
I don’t understand why Boron behaves differently than Carbon with regard to the octet rule, nor do I understand why you seem concerned only with one of the empty p orbitals when there are two? Also, what about the 3rd p orbital with only one electron? Aren’t there features about Boron’s reactivity that are tied to that fact?
Could you please provide more explanation about Boron’s unique behaviors that relate to the s orbitals, the 2 empty p orbitals, the 1/2 filled P orbital, and hybridization possibilities?
When alkyl group is kicked by B then why does it attacks the Oxygen bound to B and not the other oxygen?
Thank you for the video, amazing explanation. I do have a question though, if we are in a basic solution and it is okay to have OH-, and it was reactive earlier on and attacked the Boron when it was linked to 3 O_R, does OH- at the end continue to break and form bonds with B(OH)3?
Boron bound to oxygen has different reactivity when compared to boron with H
This video helped a lot. Thank You
thanks for this video..even it is a little tricky but its okay Ive already got an idea from this video. 🙂
What did you find tricky about the video Rogieto?