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Naming the Enyne – Alkene/Alkyne in Same Molecule

March 19, 2013 By Leah4sci 11 Comments

Nomenclature Enynes Video Tutorial Organic Chemistry Leah FischNaming Organic Compounds Series: Video 8
This Leah4sci tutorial video takes you through a systematic approach to IUPAC nomenclature for naming both and alkene and an alkyne on the same molecule. This is known as an ‘enyne'. Examples include simple and substituted enyne examples


(Watch on YouTube: Enyne. Click CC on bottom right for transcript.)

<– Watch Previous Video: Naming Alkynes
–> Watch Next Video: Naming Alkyl Halides

This is Video 8 in the Naming Organic Compounds Video Series. Click HERE for the entire series.

Need a review on Functional Groups? Watch the Functional Groups Video, Download the Cheat Sheet, then try the Quiz.

Filed Under: Nomenclature Tagged With: nomenclature

Comments

  1. Deshan Wolfey says

    May 19, 2018 at 1:22 am

    7-methyloct-3-en-5-yne is the correct name for the last compound on the video!

    Reply
  2. Jared says

    August 21, 2017 at 8:03 pm

    In naming Enyne, why do you need to put #1 (1:10) in “ene” (hex-1-ene-4-yne)? What is the difference between “hex-1-ene-4-yne” and “hexene-4-yne”?

    Reply
  3. abhilay says

    July 7, 2015 at 9:27 am

    I mean… which is correct?
    4-methyl-pent-2-ene
    or
    2-methyl-pent-3-ene

    OOPS! I think i have solved it (if the answer is second one) …. Sorry for trouble!

    Reply
  4. Unzeela says

    November 2, 2014 at 8:50 am

    Awsome effort .. but there is some error in video and i m trying to learn the iupac naming in which the molecule have both double & triple bond 🙁 video isn’t playing …what do i do ? 🙁

    Reply
    • Leah4sci says

      November 2, 2014 at 3:21 pm

      It could be an issue with your browser. Try another browser or another computer/laptop/tablet/phone

      Reply
  5. lololove11 says

    June 5, 2014 at 10:26 pm

    i love your videos but i was confused with the last example of having double bond, triple bond, and substituent …. why did you give methyl priority ?? shouldn’t we give it to the double bond ??

    Reply
    • Leah4sci says

      June 5, 2014 at 10:36 pm

      Good question. Numbering in this case is about getting the total lowest set of numbers. Starting from the left yields a pi bond at C#3, starting from the right results in a methyl at C#2

      Reply
  6. Himasha says

    January 28, 2014 at 1:02 am

    when we have triple bond ,double bond and substituents in same compound. In the case where each triple and double bond would have the same position number we learned the double bond takes the lower number. But in this video u said the lower number takes substituents.why are you saying like that way?is it mistake? or can u give me a explanation madam

    Reply
    • Leah4sci says

      January 28, 2014 at 2:29 pm

      At which point in the video are you asking about? There are some errors in my videos (I am human after all) so I want to double-check before answering.

      Reply
  7. sam says

    January 13, 2014 at 9:19 pm

    Why is it that Ene gets priority when they can be numbered the same? Is it because e comes before y in the alphabet?

    Reply
    • Leah4sci says

      January 13, 2014 at 9:50 pm

      You are correct Sam

      Reply

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